2(3y^2-x^2)=0

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Solution for 2(3y^2-x^2)=0 equation:


Simplifying
2(3y2 + -1x2) = 0

Reorder the terms:
2(-1x2 + 3y2) = 0
(-1x2 * 2 + 3y2 * 2) = 0
(-2x2 + 6y2) = 0

Solving
-2x2 + 6y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6y2' to each side of the equation.
-2x2 + 6y2 + -6y2 = 0 + -6y2

Combine like terms: 6y2 + -6y2 = 0
-2x2 + 0 = 0 + -6y2
-2x2 = 0 + -6y2
Remove the zero:
-2x2 = -6y2

Divide each side by '-2'.
x2 = 3y2

Simplifying
x2 = 3y2

Take the square root of each side:
x = {-1.732050808y, 1.732050808y}

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